5[c-2]=2[c+1]

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Solution for 5[c-2]=2[c+1] equation:


Simplifying
5[c + -2] = 2[c + 1]

Reorder the terms:
5[-2 + c] = 2[c + 1]
[-2 * 5 + c * 5] = 2[c + 1]
[-10 + 5c] = 2[c + 1]

Reorder the terms:
-10 + 5c = 2[1 + c]
-10 + 5c = [1 * 2 + c * 2]
-10 + 5c = [2 + 2c]

Solving
-10 + 5c = 2 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-10 + 5c + -2c = 2 + 2c + -2c

Combine like terms: 5c + -2c = 3c
-10 + 3c = 2 + 2c + -2c

Combine like terms: 2c + -2c = 0
-10 + 3c = 2 + 0
-10 + 3c = 2

Add '10' to each side of the equation.
-10 + 10 + 3c = 2 + 10

Combine like terms: -10 + 10 = 0
0 + 3c = 2 + 10
3c = 2 + 10

Combine like terms: 2 + 10 = 12
3c = 12

Divide each side by '3'.
c = 4

Simplifying
c = 4

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